Two trains depart simultaneously from different stations and travel towards each other at 20 km/hr and 25 km/hr speeds, respectively. Upon meeting, it becomes apparent that one train has covered a distance 80 kilometres longer than the other. Determine the total distance between the two stations.
Question
Two trains depart simultaneously from different stations and travel towards each other at 20 km/hr and 25 km/hr speeds, respectively. Upon meeting, it becomes apparent that one train has covered a distance 80 kilometres longer than the other. Determine the total distance between the two stations.
Solution 1
Let's denote the time it takes for the two trains to meet as T (in hours).
Since the two trains are moving towards each other, their combined speed is 20 km/hr + 25 km/hr = 45 km/hr.
Therefore, the total distance D (in km) between the two stations is the combined speed multiplied by the time, or D = 45T.
We also know that one train has traveled 80 km more than the other. So if we denote the distance traveled by the slower train as d (in km), then the distance traveled by the faster train is d + 80 km.
Since the slower train travels at 20 km/hr, its distance d is 20T. Similarly, since the faster train travels at 25 km/hr, its distance is 25T.
Therefore, we can set up the equation 20T + 80 = 25T. Solving for T, we get T = 80 / 5 = 16 hours.
Substituting T = 16 into the equation for D, we get D = 45 * 16 = 720 km.
Therefore, the total distance between the two stations is 720 km.
Solution 2
Let's denote the time it takes for the two trains to meet as T (in hours).
Since the two trains are moving towards each other, their combined speed is 20 km/hr + 25 km/hr = 45 km/hr.
Therefore, the total distance D (in km) between the two stations is the combined speed multiplied by the time, or D = 45T.
We also know that one train has traveled 80 km more than the other. So if we denote the distance traveled by the slower train as d1 and the distance traveled by the faster train as d2, we have d2 = d1 + 80.
Since the slower train travels at 20 km/hr, its distance d1 = 20T.
Since the faster train travels at 25 km/hr, its distance d2 = 25T.
Substituting d1 and d2 into the equation d2 = d1 + 80, we get 25T = 20T + 80.
Solving for T, we get T = 80 / (25 - 20) = 16 hours.
Substituting T = 16 into the equation D = 45T, we get D = 45 * 16 = 720 km.
So the total distance between the two stations is 720 km.
Solution 3
Let's denote the time at which the two trains meet as T.
Since the speed of the first train is 20 km/hr, in time T it will cover a distance of 20T km.
Similarly, the second train, moving at a speed of 25 km/hr, will cover a distance of 25T km in the same time.
According to the problem, one train travels 80 km more than the other by the time they meet. So we can write the equation:
25T = 20T + 80
Solving this equation for T gives us T = 16 hours.
So, the two trains meet 16 hours after they start traveling.
Now, to find the total distance between the two stations, we need to add the distances each train covered in that time.
The first train covered 20 km/hr * 16 hr = 320 km.
The second train covered 25 km/hr * 16 hr = 400 km.
Adding these two distances together gives us the total distance between the two stations:
320 km + 400 km = 720 km.
So, the total distance between the two stations is 720 kilometers.
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