A cyclist travels a certain distance in 6 hours at a uniform speed. In return, he increases his speed by 2 kmph. and covers the same distance in 5 hours. What was his speed initially?Options10 kmph12.5 kmph10.5 kmph.12 kmph
Question
A cyclist travels a certain distance in 6 hours at a uniform speed. In return, he increases his speed by 2 kmph. and covers the same distance in 5 hours. What was his speed initially?Options10 kmph12.5 kmph10.5 kmph.12 kmph
Solution
Let's denote the initial speed of the cyclist as x kmph. Therefore, the distance he travels is 6x.
When he returns, his speed is x + 2 kmph, and he covers the same distance in 5 hours. Therefore, we can write the equation:
5(x + 2) = 6x
Solving this equation will give us the initial speed of the cyclist.
5x + 10 = 6x
Subtract 5x from both sides:
10 = x
Therefore, the cyclist's initial speed was 10 kmph.
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