Let's denote the distance Daniel walked as W (in km) and the distance he cycled as C (in km). We know that the total distance covered (W + C) is 36 km.

We also know that the total time spent walking and cycling is 8 hours. Given that speed is distance over time, we can express the time spent walking as W/4 and the time spent cycling as C/6.

So, we have two equations:

1) W + C = 36
2) W/4 + C/6 = 8

We can solve this system of equations step by step:

First, let's multiply the second equation by 12 to get rid of the fractions:

3W + 2C = 96

Now we have:

1) W + C = 36
3) 3W + 2C = 96

We can multiply the first equation by 2:

2) 2W + 2C = 72

Now, let's subtract the second equation from the third:

3) 3W + 2C = 96
2) - (2W + 2C = 72)
--------------------------
Result: W = 24

So, Daniel walked 24 km.

Question

Let's denote the distance Daniel walked as W (in km) and the distance he cycled as C (in km). We know that the total distance covered (W + C) is 36 km.

We also know that the total time spent walking and cycling is 8 hours. Given that speed is distance over time, we can express the time spent walking as W/4 and the time spent cycling as C/6.

So, we have two equations:

1) W + C = 36
2) W/4 + C/6 = 8

We can solve this system of equations step by step:

First, let's multiply the second equation by 12 to get rid of the fractions:

3W + 2C = 96

Now we have:

1) W + C = 36
3) 3W + 2C = 96

We can multiply the first equation by 2:

2) 2W + 2C = 72

Now, let's subtract the second equation from the third:

3) 3W + 2C = 96
2) - (2W + 2C = 72)
--------------------------
Result: W = 24

So, Daniel walked 24 km.

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