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Kavitha travelled a distance of 40 km in 6 hours . She travelled partly on foot at 4 kmph and partly on bicycle at 8 kmph . What is the distance travelled by foot ?

Question

Kavitha travelled a distance of 40 km in 6 hours . She travelled partly on foot at 4 kmph and partly on bicycle at 8 kmph . What is the distance travelled by foot ?

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Solution

Let's denote the time Kavitha spent walking as T1 and the time she spent biking as T2. We know that T1 + T2 = 6 hours.

We also know that the total distance she traveled is 40 km, which is the sum of the distance she walked and the distance she biked. We can express the distance as the product of speed and time, so we have 4T1 (the distance she walked) + 8T2 (the distance she biked) = 40 km.

We now have a system of two equations, and we can solve it step by step:

  1. Express T2 from the first equation: T2 = 6 - T1.
  2. Substitute T2 in the second equation: 4T1 + 8(6 - T1) = 40.
  3. Simplify the equation: 4T1 + 48 - 8T1 = 40.
  4. Combine like terms: -4*T1 = -8.
  5. Solve for T1: T1 = 2 hours.

So, Kavitha spent 2 hours walking. To find the distance she walked, multiply the time by her speed: 4 km/h * 2 h = 8 km.

Therefore, Kavitha travelled 8 km on foot.

This problem has been solved

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