f the point (y, 8) lies on a circle whose center is at the origin and radius is 17 cm, then y is equal to
Question
f the point (y, 8) lies on a circle whose center is at the origin and radius is 17 cm, then y is equal to
Solution
The equation of a circle centered at the origin (0,0) with radius r is x² + y² = r².
Given that the point (y, 8) lies on the circle, we can substitute x with y and y with 8 in the equation. The radius r is given as 17 cm.
So, the equation becomes:
y² + 8² = 17²
Solving this equation will give us the possible values for y.
First, simplify the equation:
y² + 64 = 289
Then, subtract 64 from both sides to isolate y²:
y² = 289 - 64 y² = 225
Finally, take the square root of both sides. Remember that the square root of a number can be either positive or negative:
y = sqrt(225) = ±15
So, the point (y, 8) could be either (15, 8) or (-15, 8).
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