Yes, we can conclude that the equation q(x)=0 has a solution. This is because of the Intermediate Value Theorem, which states that if a function is continuous on a closed interval [a,b], and k is any number between f(a) and f(b), then there is at least one number c in the interval [a,b] such that f(c)=k.

In this case, q(x) is a polynomial, and polynomials are continuous everywhere, including on the interval [-19,2]. We have q(-19)=4 and q(-12)=7, so if we let k=0, there must be a number c in the interval [-19,-12] such that q(c)=0. Therefore, the equation q(x)=0 has a solution.

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Yes, we can conclude that the equation q(x)=0 has a solution. This is because of the Intermediate Value Theorem, which states that if a function is continuous on a closed interval [a,b], and k is any number between f(a) and f(b), then there is at least one number c in the interval [a,b] such that f(c)=k.

In this case, q(x) is a polynomial, and polynomials are continuous everywhere, including on the interval [-19,2]. We have q(-19)=4 and q(-12)=7, so if we let k=0, there must be a number c in the interval [-19,-12] such that q(c)=0. Therefore, the equation q(x)=0 has a solution.

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Yes, we can conclude that the equation q(x)=0 has a solution. This is because of the Intermediate Value Theorem, which states that if a function is continuous on a closed interval [a,b], and k is any number between f(a) and f(b), then there is at least one number c in the interval [a,b] such that f(c)=k.

In this case, q(x) is a polynomial, and polynomials are continuous everywhere, including on the interval [-19,2]. We have q(-19)=4 and q(-12)=7, so if we let k=0, there must be a number c in the interval [-19,-12] such that q(c)=0. Therefore, the equation q(x)=0 has a solution.

The table below shows certain values of q(x) on the interval [–19,2].x q(x)–19 4–12 7–5 102 10If q(x) is a polynomial, can you conclude that the equation q(x)=0 has a solution?

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