To find the integer values of x that satisfy the polynomial equation x^3 + 3x^2 - 6x - 16 = 0, we can use the Rational Root Theorem. This theorem states that any rational root, p/q, of the polynomial must have p as a factor of the constant term (-16 in this case) and q as a factor of the leading coefficient (1 in this case).

The factors of -16 are ±1, ±2, ±4, ±8, ±16. Since the leading coefficient is 1, the possible rational roots are the same as the factors of -16.

We can test these possible roots by substituting them into the equation and checking if the equation holds true.

If we do this, we find that the integer values of x that satisfy the equation are x = -4, x = 2, and x = -2.

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To find the integer values of x that satisfy the polynomial equation x^3 + 3x^2 - 6x - 16 = 0, we can use the Rational Root Theorem. This theorem states that any rational root, p/q, of the polynomial must have p as a factor of the constant term (-16 in this case) and q as a factor of the leading coefficient (1 in this case).

The factors of -16 are ±1, ±2, ±4, ±8, ±16. Since the leading coefficient is 1, the possible rational roots are the same as the factors of -16.

We can test these possible roots by substituting them into the equation and checking if the equation holds true.

If we do this, we find that the integer values of x that satisfy the equation are x = -4, x = 2, and x = -2.

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To find the integer values of x that satisfy the polynomial equation x^3 + 3x^2 - 6x - 16 = 0, we can use the Rational Root Theorem. This theorem states that any rational root, p/q, of the polynomial must have p as a factor of the constant term (-16 in this case) and q as a factor of the leading coefficient (1 in this case).

The factors of -16 are ±1, ±2, ±4, ±8, ±16. Since the leading coefficient is 1, the possible rational roots are the same as the factors of -16.

We can test these possible roots by substituting them into the equation and checking if the equation holds true.

If we do this, we find that the integer values of x that satisfy the equation are x = -4, x = 2, and x = -2.

Find out all integer values of x that satisfy the following polynomial equation:x3+ 3x2- 6x - 16 = 0

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