What will happen if the following C code is executed?#include <stdio.h>    int main()    {        int main = 3;        printf("%d", main);        return 0;    }It will experience infinite loopingIt will cause a run-time errorIt will cause a compile-time errorIt will run without any error and prints 3

The code will run without any error and prints 3.

Here's the step by step explanation:

1. The program starts with the inclusion of the stdio.h header file which is used for input/output operations in C.

2. The main function is declared. This is the entry point of the program.

3. Inside the main function, an integer variable named 'main' is declared and initialized with the value 3.

4. The printf function is called to print the value of the 'main' variable. Since the 'main' variable holds the value 3, the output will be 3.

5. The main function returns 0 indicating successful execution of the program.

So, the program will run without any error and print the value 3.