Select the correct answerWhat is the output of the following program?public class Nptel{ public static void main(String[] args) { try { int a = 5 / 0; } catch (Exception e) { catch (ArithmeticException a) { } } System.out.println("Programming In Java"); }}Options“Programming In Java”Compile time errorArithmeticExceptionRun time error
Question
Select the correct answerWhat is the output of the following program?public class Nptel{ public static void main(String[] args) { try { int a = 5 / 0; } catch (Exception e) { catch (ArithmeticException a) { } } System.out.println("Programming In Java"); }}Options“Programming In Java”Compile time errorArithmeticExceptionRun time error
Solution
The correct answer is "Compile time error".
The reason is that the catch block inside another catch block is not allowed in Java. The correct way to catch multiple exceptions is to have multiple catch blocks, one after another. So, the nested catch block will cause a compile time error.
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