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Select the correct answerWhat is the output of the following program?public class Nptel extends Thread { public void run() { for (int i = 1; i < 5; i++) { System.out.print(i++ + " "); } } public static void main(String args[]) { Nptel t1 = new Nptel(); t1.run(); }}Options1 2 3 41 3Runtime error1 2

Question

Select the correct answerWhat is the output of the following program?public class Nptel extends Thread { public void run() { for (int i = 1; i < 5; i++) { System.out.print(i++ + " "); } } public static void main(String args[]) { Nptel t1 = new Nptel(); t1.run(); }}Options1 2 3 41 3Runtime error1 2

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Solution

The correct answer is "1 3".

Here's the step-by-step explanation:

  1. The run() method of the Nptel class is called in the main method. This run() method contains a for loop that iterates from 1 to 4 (i.e., less than 5).

  2. Inside the for loop, the System.out.print(i++ + " ") statement is executed. This statement prints the current value of i and then increments i by 1 due to the post-increment operator (i++).

  3. So, in the first iteration, i is 1. It prints 1 and then increments i to 2.

  4. In the second iteration, i is now 2. It prints 2 and then increments i to 3. But due to the i++ in the print statement, i is incremented again to 4.

  5. In the third iteration, i is now 4. It prints 4 and then increments i to 5. But since the loop condition is i < 5, the loop ends here.

  6. Therefore, the output of the program is "1 3".

This problem has been solved

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