This problem can be solved using Python. Here is a step-by-step guide on how to do it:

Step 1: Define a function that takes an integer as an argument.

```python
def sum_of_squares(n):
```

Step 2: Initialize a variable to store the sum of the squares of the digits.

```python
sum = 0
```

Step 3: Use a do-while loop to iterate through each digit in the number. In Python, we don't have a built-in do-while loop, but we can create one using a while loop with a condition that is always true, and then break the loop when a certain condition is met.

```python
while True:
digit = n % 10
sum += digit ** 2
n //= 10
if n == 0:
break
```

In this loop, we first get the last digit of the number by taking the modulus of the number with 10. We then add the square of this digit to our sum. We then remove this digit from the number by doing integer division by 10. We continue this process until there are no more digits left in the number.

Step 4: Return the sum.

```python
return sum
```

So, the complete function is:

```python
def sum_of_squares(n):
sum = 0
while True:
digit = n % 10
sum += digit ** 2
n //= 10
if n == 0:
break
return sum
```

You can then call this function with a number to get the sum of the squares of its digits. For example:

```python
print(sum_of_squares(55)) # Output: 50
```

Question

This problem can be solved using Python. Here is a step-by-step guide on how to do it:

Step 1: Define a function that takes an integer as an argument.

```python
def sum_of_squares(n):
```

Step 2: Initialize a variable to store the sum of the squares of the digits.

```python
    sum = 0
```

Step 3: Use a do-while loop to iterate through each digit in the number. In Python, we don't have a built-in do-while loop, but we can create one using a while loop with a condition that is always true, and then break the loop when a certain condition is met.

```python
    while True:
        digit = n % 10
        sum += digit ** 2
        n //= 10
        if n == 0:
            break
```

In this loop, we first get the last digit of the number by taking the modulus of the number with 10. We then add the square of this digit to our sum. We then remove this digit from the number by doing integer division by 10. We continue this process until there are no more digits left in the number.

Step 4: Return the sum.

```python
    return sum
```

So, the complete function is:

```python
def sum_of_squares(n):
    sum = 0
    while True:
        digit = n % 10
        sum += digit ** 2
        n //= 10
        if n == 0:
            break
    return sum
```

You can then call this function with a number to get the sum of the squares of its digits. For example:

```python
print(sum_of_squares(55))  # Output: 50
```

Knowee AI · Accepted Answer