Given that p2+q2=228 and pq=86, find the value of (p+q)2.
Question
Given that p2+q2=228 and pq=86, find the value of (p+q)2.
Solution
Sure, let's solve this step by step.
The formula for the square of a sum is (p+q)² = p² + 2pq + q².
We know that p² + q² = 228 and pq = 86.
Substitute these values into the formula:
(p+q)² = 228 + 2*86.
Calculate 2*86 = 172.
Then add 228 + 172 = 400.
So, (p+q)² = 400.
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