What is the maximum possible height of a 0.15 kg baseball if it has 90 J of kinetic energy after being hit by a baseball bat?A.130 mB.90 mC.60 mD.9.0 mSubmit

To solve this problem, we need to use the principle of conservation of energy. The kinetic energy of the baseball after being hit will be converted into potential energy when the baseball reaches its maximum height.

The formula for kinetic energy (KE) is KE = 1/2 * m * v^2, where m is the mass and v is the velocity. The formula for potential energy (PE) is PE = m * g * h, where m is the mass, g is the gravitational acceleration (approximately 9.8 m/s^2 on Earth), and h is the height.

Since the kinetic energy will be converted into potential energy, we can set the two equal to each other and solve for h:

1/2 * m * v^2 = m * g * h

We know that m = 0.15 kg, g = 9.8 m/s^2, and the kinetic energy is 90 J. We can substitute these values into the equation and solve for h:

90 J = 0.15 kg * 9.8 m/s^2 * h

Solving for h gives us h = 90 J / (0.15 kg * 9.8 m/s^2) = 612.24 m

However, this value is not in the options provided. There might be a mistake in the problem or the options. If we assume that the kinetic energy is equal to the potential energy (which is a reasonable assumption if we ignore air resistance and other factors), then the maximum height should be much larger than any of the options provided.