What is the output of this code ( In Python )? l1 = [1, [2, 3], 4] l2 = l1.copy() l2[1][1]=7 print(l1, l2)

To determine the output of the given code, let's break it down step by step:

1. Initialize a list l1 with elements [1, [2, 3], 4].
2. Create a copy of l1 and assign it to l2 using the copy() method.
3. Modify the second element of l2 by accessing l2[1][1] and assigning it the value 7.
4. Print both l1 and l2.

The output of the code will be: [1, [2, 7], 4] [1, [2, 7], 4]

Explanation: When we create a copy of l1 using the copy() method, it creates a shallow copy. This means that the outer list l2 is a new list, but the inner list [2, 3] is still referenced by both l1 and l2. Therefore, when we modify the second element of l2, it also affects l1. Hence, both l1 and l2 will have the modified value [2, 7] in the second element.