What is the output of the following code?L = [1, 3, 5, 7, 9]print(L.pop(-3), end = ' ')print(L.remove(L[0]), end = ' ')print(L)1 point5 1 [3, 9, 7]5 1 [3, 7, 9]5 None [3, 7, 9]5 None [1, 3, 7, 9]
Question
What is the output of the following code?L = [1, 3, 5, 7, 9]print(L.pop(-3), end = ' ')print(L.remove(L[0]), end = ' ')print(L)1 point5 1 [3, 9, 7]5 1 [3, 7, 9]5 None [3, 7, 9]5 None [1, 3, 7, 9]
Solution
To determine the output of the given code, let's break it down step by step:
- Initialize a list L with the values [1, 3, 5, 7, 9].
- The first print statement, L.pop(-3), removes and returns the element at index -3, which is 5. So, the output of this statement is 5.
- The second print statement, L.remove(L[0]), removes the element at index 0, which is 1. However, the remove() method does not return any value, so the output of this statement is None.
- Finally, the third print statement, print(L), prints the updated list L after the previous operations. The list L now contains [3, 7, 9].
Therefore, the correct output is: 5 None [3, 7, 9].
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