If x - a is a factor of the polynomial x^3 - ax^2 + 2x + a - 1, then by the Factor Theorem, substituting x = a into the polynomial should yield 0.

So, we substitute x = a into the polynomial:

a^3 - a*a^2 + 2a + a - 1 = 0
a^3 - a^3 + 2a + a - 1 = 0
3a - 1 = 0

Solving this equation for a gives:

3a = 1
a = 1/3

So, the value of a is 1/3.

Question

If x - a is a factor of the polynomial x^3 - ax^2 + 2x + a - 1, then by the Factor Theorem, substituting x = a into the polynomial should yield 0.

So, we substitute x = a into the polynomial:

a^3 - a*a^2 + 2a + a - 1 = 0
a^3 - a^3 + 2a + a - 1 = 0
3a - 1 = 0

Solving this equation for a gives:

3a = 1
a = 1/3

So, the value of a is 1/3.

Knowee AI · Accepted Answer

If x - a is a factor of the polynomial x^3 - ax^2 + 2x + a - 1, then by the Factor Theorem, substituting x = a into the polynomial should yield 0.

So, we substitute x = a into the polynomial:

a^3 - a*a^2 + 2a + a - 1 = 0
a^3 - a^3 + 2a + a - 1 = 0
3a - 1 = 0

Solving this equation for a gives:

3a = 1
a = 1/3

So, the value of a is 1/3.

Find the value of a, if x – a is a factor of x3 – ax2 + 2x + a – 1