Sure, let's factorise the given expression step by step:

The given expression is: x² – 1 – 2a – a²

First, we can rearrange the terms to group the x terms and the a terms together:

x² – 1 – a² + 2a

Next, we can recognise that the first two terms and the last two terms are both differences of squares. We can factorise each of these separately:

(x - 1)(x + 1) - (a - 1)(a + 1)

So, the factorised form of the given expression is:

(x - 1)(x + 1) - (a - 1)(a + 1)

Question

Sure, let's factorise the given expression step by step:

The given expression is: x² – 1 – 2a – a²

First, we can rearrange the terms to group the x terms and the a terms together:

x² – 1 – a² + 2a

Next, we can recognise that the first two terms and the last two terms are both differences of squares. We can factorise each of these separately:

(x - 1)(x + 1) - (a - 1)(a + 1)

So, the factorised form of the given expression is:

(x - 1)(x + 1) - (a - 1)(a + 1)

Knowee AI · Accepted Answer

Sure, let's factorise the given expression step by step:

The given expression is: x² – 1 – 2a – a²

First, we can rearrange the terms to group the x terms and the a terms together:

x² – 1 – a² + 2a

Next, we can recognise that the first two terms and the last two terms are both differences of squares. We can factorise each of these separately:

(x - 1)(x + 1) - (a - 1)(a + 1)

So, the factorised form of the given expression is:

(x - 1)(x + 1) - (a - 1)(a + 1)

Factorise: x2 – 1 – 2a – a2