Given ๐ข=๐ฅ2+๐ฅ๐ฆ+๐ฆ2, solve for โ๐ขโ๐ฅ
Question
Given ๐ข=๐ฅ2+๐ฅ๐ฆ+๐ฆ2, solve for โ๐ขโ๐ฅ
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Solution
To solve for โ๐ข/โ๐ฅ, we need to take the partial derivative of ๐ข with respect to ๐ฅ.
The given function is ๐ข=๐ฅยฒ+๐ฅ๐ฆ+๐ฆยฒ.
The partial derivative of ๐ข with respect to ๐ฅ is obtained by differentiating each term of ๐ข with respect to ๐ฅ, while treating all other variables as constants.
- The derivative of ๐ฅยฒ with respect to ๐ฅ is 2๐ฅ.
- The derivative of ๐ฅ๐ฆ with respect to ๐ฅ is ๐ฆ (since the derivative of ๐ฅ is 1 and ๐ฆ is treated as a constant).
- The derivative of ๐ฆยฒ with respect to ๐ฅ is 0 (since ๐ฆยฒ is a constant with respect to ๐ฅ).
So, โ๐ข/โ๐ฅ = 2๐ฅ + ๐ฆ.
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