To find the Highest Common Factor (HCF) of the given numbers, we need to take the lowest power of each prime factor common to all the numbers.

The prime factors are 2, 3, 5, and 7.

1. For 2, the powers in the three numbers are 3, 2, and 3. The lowest power is 2.
2. For 3, the powers in the three numbers are 2, 0, and 0. The lowest power is 0.
3. For 5, the powers in the three numbers are 1, 2, and 3. The lowest power is 1.
4. For 7, the powers in the three numbers are 2, 3, and 2. The lowest power is 2.

So, the HCF is 2² x 3⁰ x 5¹ x 7² = 4 x 1 x 5 x 49 = 980.

Question

To find the Highest Common Factor (HCF) of the given numbers, we need to take the lowest power of each prime factor common to all the numbers.

The prime factors are 2, 3, 5, and 7.

1. For 2, the powers in the three numbers are 3, 2, and 3. The lowest power is 2.
2. For 3, the powers in the three numbers are 2, 0, and 0. The lowest power is 0.
3. For 5, the powers in the three numbers are 1, 2, and 3. The lowest power is 1.
4. For 7, the powers in the three numbers are 2, 3, and 2. The lowest power is 2.

So, the HCF is 2² x 3⁰ x 5¹ x 7² = 4 x 1 x 5 x 49 = 980.

Knowee AI · Accepted Answer

To find the Highest Common Factor (HCF) of the given numbers, we need to take the lowest power of each prime factor common to all the numbers.

The prime factors are 2, 3, 5, and 7.

1. For 2, the powers in the three numbers are 3, 2, and 3. The lowest power is 2.
2. For 3, the powers in the three numbers are 2, 0, and 0. The lowest power is 0.
3. For 5, the powers in the three numbers are 1, 2, and 3. The lowest power is 1.
4. For 7, the powers in the three numbers are 2, 3, and 2. The lowest power is 2.

So, the HCF is 2² x 3⁰ x 5¹ x 7² = 4 x 1 x 5 x 49 = 980.

Find the HCF of 2³ x 3² x 5 x 7^2; 2² x 5² x 7³ and 2³ x 5³ x 7²

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