HCF of (23×32×5),(2 3 ×3 2 ×5), (22×33×52)(2 2 ×3 3 ×5 2 ) and (24×3×53×7)(2 4 ×3×5 3 ×7) is ______

The Highest Common Factor (HCF) is found by multiplying the highest power of all common prime factors.

The prime factors common to all the given numbers are 2, 3, and 5.

The lowest power of 2 in all the given numbers is 2 (in the third number). The lowest power of 3 in all the given numbers is 2 (in the first and second numbers). The lowest power of 5 in all the given numbers is 1 (in the first and second numbers).

So, the HCF of the given numbers is 2^2 × 3^2 × 5^1 = 4 × 9 × 5 = 180.