Analyze the following code: public class Test {   public static void main(String[] args) {     String s = new String("Welcome to Java");     Object o = s;     String d = (String)o;   }   } Group of answer choicesWhen assigning s to o in Object o = s, a new object is created.When casting o in String d = (String)o, a new object is created.When casting o in String d = (String)o, the contents of o is changed.s, o, and d reference the same String object.

What is the output of the following code? _____public class Test {    public static void main(String[] args) {    String s1 = "Welcome to Java!";    String s2 = s1;    if (s1 == s2)      System.out.println("s1 and s2 reference to the same String object");    else      System.out.println("s1 and s2 reference to different String objects");  }}A. s1 and s2 reference to the same String objectB. s1 and s2 reference to different String objects

n Java, what happens when you reassign a modified String to the same reference variable, as shown in the code below?String s = "Hello";s = s.concat(" World");a)The original String is updated in placeb)The reference variable s is deletedc)A new reference variable is createdd)A new String object is created, and s refers to it

Analyze the following code carefully. public class Test {   int x;   public Test(String t) {      System.out.println("Test");   }   public static void main(String[] args) {     Test test = null;     System.out.println(test.x);   } } Group of answer choicesThe program has a compile error because test is not initialized.The program has a compile error because x has not been initialized.The program has a compile error because you cannot create an object from the class that defines the object.The program has a compile error because Test does not have a default constructor.The program has a runtime NullPointerException because test is null while executing test.x.

Analyze the following code. Please select all that apply.  public class Test {   public static void main(String[] args) {     Object a1 = new A();     Object a2 = new Object();     System.out.println(a1);     System.out.println(a2);   } } class A {   int x;   @Override   public String toString() {     return "A's x is " + x;   } } Group of answer choicesThe program cannot be compiled, because System.out.println(a1) is wrong and it should be replaced by System.out.println(a1.toString());When executing System.out.println(a1), the toString() method in the Object class is invoked.When executing System.out.println(a2), the toString() method in the Object class is invoked.When executing System.out.println(a1), the toString() method in the A class is invoked.

Analyze the following code carefully. Please select the one that applies.public class Test {  public static void main(String[] args) {    A a = new A();    a.print();  }}class A {  String s;  A(String s) {    this.s = s;  }void print() {    System.out.println(s);  }}