Analyze the following code carefully. Please select the one that applies.public class Test { public static void main(String[] args) { A a = new A(); a.print(); }}class A { String s; A(String s) { this.s = s; }void print() { System.out.println(s); }}
Question
Analyze the following code carefully. Please select the one that applies.public class Test { public static void main(String[] args) { A a = new A(); a.print(); }}class A { String s; A(String s) { this.s = s; }void print() { System.out.println(s); }}
Solution
The code you provided will not compile successfully. The reason is that you're trying to create an instance of class A using a no-argument constructor A a = new A(); but in your class definition, you have only defined a constructor that accepts a String argument A(String s).
To fix this issue, you can either provide a String when creating a new instance of A like A a = new A("some string"); or you can define a no-argument constructor in your class A like:
A() {
this.s = "";
}
This way, you can create a new instance of A without providing a String.
Similar Questions
Analyze the following code carefully. Please select all that apply. public class Test { public static void main(String[] args) { A a = new A(); a.print(); } } class A { String s; A(String s) { this.s = s; } void print() { System.out.println(s); } } Group of answer choicesThe program has a compile error because class A is not a public class.The program has a compile error because class A does not have a default constructor.The program compiles and runs fine and prints nothing.The program would compile and run if you change A a = new A() to A a = new A("5").
public class Test { public void m1(String arg1) { arg1="Test"; } public static void main(String[] args) { Test test1= new Test(); String s= "Hello"; test1.m1(s); System.out.println(s); }}
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