public class Code { public static void main(String[] args) { method(null); } public static void method(Object o) { System.out.println("Object method"); } public static void method(String s) { System.out.println("String method"); }}
Question
public class Code { public static void main(String[] args) { method(null); } public static void method(Object o) { System.out.println("Object method"); } public static void method(String s) { System.out.println("String method"); }}
Solution
When you run this Java program, it will output "String method".
Here's the step by step explanation:
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The main method is the entry point of the program. It calls the method with a null argument.
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Java uses method overloading, which allows multiple methods to have the same name but different parameters. In this case, there are two methods named "method". One takes an Object as a parameter and the other takes a String.
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When calling a method, Java uses the most specific method that is applicable. In this case, null can be passed to both the method that accepts an Object and the method that accepts a String. However, since String is more specific than Object, the method with the String parameter is chosen.
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Therefore, "String method" is printed to the console.
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