n C, what does the expression arr[2] + arr[4] represent for the array "arr"?
Question
n C, what does the expression arr[2] + arr[4] represent for the array "arr"?
Solution
The expression arr[2] + arr[4] in C represents the sum of the third and fifth elements of the array arr.
Here's how it works:
-
arr[2]accesses the third element in the arrayarr. In C, array indexing starts from 0, soarr[2]refers to the third element. -
arr[4]accesses the fifth element in the arrayarr. -
The
+operator then adds these two elements together.
So, if arr was defined and initialized as int arr[] = {1, 2, 3, 4, 5};, arr[2] + arr[4] would give you 3 + 5 = 8.
Similar Questions
What is the output of the following code?#include <stdio.h>int main() { int arr[2][2] = {{1, 2}, {3, 4}}; printf("%d\n", arr[0][2]); return 0;}
What is the output of the following code?int arr[] = {1, 2, 3, 4, 5};int i;for (i = 0; i < 5; i++) arr[i] = arr[i] + 2;printf("%d\n", arr[3]);
What is the output of the following code?#include <stdio.h>void modifyArray(int arr[], int size) { for (int i = 0; i < size; i++) { arr[i] = arr[i] * 2; }}int main() { int arr[] = {1, 2, 3, 4, 5}; int size = sizeof(arr) / sizeof(arr[0]); modifyArray(arr, size); printf("%d\n", arr[2]); return 0;}
What is the value of 'arr[2]' after the second pass?
Below is an array declaration in 'C' language:int ar1[] = {2,9};int ar2[3] = {9};What will be the output of the following print statement?printf("%d,%d", ar1[1], ar2[2]);(1 Point)
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.