Molality of 5M solution of H2SO4 having density 1.115 gm/ml is -----------

To find the molality of the solution, we need to know the number of moles of solute (H2SO4) and the mass of the solvent (water) in kilograms.

Step 1: Calculate the number of moles of H2SO4 Molarity (M) = moles of solute / volume of solution in liters So, moles of H2SO4 = Molarity * volume of solution Given that the molarity is 5M, and assuming we have 1 liter of solution, the moles of H2SO4 = 5 * 1 = 5 moles.

Step 2: Calculate the mass of the solvent (water) We know that the density (d) = mass (m) / volume (v) So, mass = density * volume Given that the density is 1.115 gm/ml, and the volume of the solution is 1 liter = 1000 ml, the mass of the solution = 1.115 * 1000 = 1115 grams.

Now, we need to subtract the mass of H2SO4 from the total mass to get the mass of the water. The molar mass of H2SO4 is approximately 98 g/mol, so the mass of H2SO4 in the solution = 5 moles * 98 g/mol = 490 grams.

So, the mass of the water = 1115 grams - 490 grams = 625 grams = 0.625 kilograms.

Step 3: Calculate the molality Molality (m) = moles of solute / mass of solvent in kilograms So, the molality of the solution = 5 moles / 0.625 kg = 8 m (mol/kg)

So, the molality of the 5M solution of H2SO4 having density 1.115 gm/ml is 8 mol/kg.