Calculate the molality of a 15.0% by mass solution of MgCl2 in H2 The density of this solution is 1.127 g/mL.Group of answer choices1.86 m0.157 m0.0134 m11.8 m1.58 m

To calculate the molality of a solution, we need to know the moles of solute and the mass of the solvent in kilograms.

1. First, let's find the mass of the solution. Since the density is 1.127 g/mL, and we have 100 mL of solution (since percentages are based on 100), the mass of the solution is 1.127 g/mL * 100 mL = 112.7 g.

2. The mass of MgCl2 in the solution is 15.0% of the total mass, so it's 15.0/100 * 112.7 g = 16.905 g.

3. Convert the mass of MgCl2 to moles. The molar mass of MgCl2 is about 95.211 g/mol, so the number of moles is 16.905 g / 95.211 g/mol = 0.177 moles.

4. The mass of the solvent (water) is the total mass of the solution minus the mass of the solute, so it's 112.7 g - 16.905 g = 95.795 g. Convert this to kilograms by dividing by 1000, so it's 0.095795 kg.

5. Finally, calculate the molality by dividing the moles of solute by the mass of the solvent in kilograms. So, the molality is 0.177 moles / 0.095795 kg = 1.85 m.

So, the closest answer is 1.86 m.