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What is the output of this C code?#include <stdio.h> struct student { char *name; }; struct student s; struct student fun(void) { s.name = "newton"; printf("%s\n", s.name); s.name = "alan"; return s; } void main() { struct student m = fun(); printf("%s\n", m.name); m.name = "turing"; printf("%s\n", s.name);

Question

What is the output of this C code?#include <stdio.h> struct student { char *name; }; struct student s; struct student fun(void) { s.name = "newton"; printf("%s\n", s.name); s.name = "alan"; return s; } void main() { struct student m = fun(); printf("%s\n", m.name); m.name = "turing"; printf("%s\n", s.name);

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Solution

The output of the C code will be:

newton alan alan

Here's the step by step explanation:

  1. The function fun() is called in the main() function.

  2. Inside fun(), the name field of the global struct student s is first set to "newton", and then it is printed, so "newton" is the first line of output.

  3. Then, the name field of s is set to "alan", and s is returned from fun().

  4. The returned struct is assigned to m in the main() function. At this point, both s and m have their name field set to "alan".

  5. The name field of m is printed, so "alan" is the second line of output.

  6. Then, the name field of m is set to "turing", but this does not affect s.

  7. Finally, the name field of s is printed, so "alan" is the third line of output.

This problem has been solved

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