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Find the volume of the solid bounded by the planes x = 1, y = 0, z = 0, theparabolic cylinder y = x2, and the surface z = xey. Sketch the region of integration

Question

Find the volume of the solid bounded by the planes x = 1, y = 0, z = 0, theparabolic cylinder y = x2, and the surface z = xey. Sketch the region of integration

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Solution 1

To find the volume of the solid bounded by the given planes and surfaces, we can use triple integration.

Step 1: Identify the limits of integration The limits of x are given by the plane x = 1, so x goes from 0 to 1. The limits of y are given by the parabolic cylinder y = x^2, so y goes from 0 to x^2. The limits of z are given by the surface z = xey and the plane z = 0, so z goes from 0 to xey.

Step 2: Set up the triple integral The volume V of the solid is given by the triple integral of dz dy dx over the region defined by the limits of integration. So,

V = ∫ from 0 to 1 ∫ from 0 to x^2 ∫ from 0 to xey dz dy dx

Step 3: Evaluate the innermost integral The innermost integral ∫ from 0 to xey dz is simply xey - 0 = xey.

Step 4: Substitute this into the integral and evaluate the next integral V = ∫ from 0 to 1 ∫ from 0 to x^2 xey dy dx This integral can be evaluated by using the method of substitution. Let u = x^2, then du = 2x dx. The limits of integration for u are 0 and x^2. So,

V = ∫ from 0 to 1 1/2 ∫ from 0 to u uey du dx

Step 5: Evaluate the innermost integral The innermost integral ∫ from 0 to u uey du is uey - ∫ey du = uey - eyu from 0 to u = uey - eyu - 0 = 0.

Step 6: Substitute this into the integral and evaluate the final integral V = ∫ from 0 to 1 0 dx = 0

So, the volume of the solid is 0.

As for the sketch of the region of integration, it's a bit difficult to describe in text. But you can imagine it as a region in the first octant (where x, y, and z are all positive) bounded by the plane x = 1, the x-axis (y = 0), the z-axis (z = 0), the parabolic cylinder y = x^2 (which opens towards the positive y-axis), and the surface z = xey (which is a kind of warped plane that gets higher as x and y increase).

This problem has been solved

Solution 2

To find the volume of the solid bounded by the given planes and surfaces, we can use triple integration. The limits of integration will be determined by the boundaries of the solid.

  1. Set up the triple integral: The volume V of the solid is given by the triple integral of dz dy dx. The integrand is 1, because we're finding volume.

  2. Determine the limits of integration:

    For x, we are given the plane x = 1. Since there's no other boundary in the x direction, we assume the solid extends to x = 0. So, 0 ≤ x ≤ 1.

    For y, we are given the parabolic cylinder y = x^2. Since there

This problem has been solved

Solution 3

To find the volume of the solid bounded by the given planes and surfaces, we can use triple integration.

Step 1: Sketch the region of integration

The region of integration is bounded by the planes x = 1, y = 0, z = 0, the parabolic cylinder y = x^2, and the surface z = xey.

  • The plane x = 1 is a vertical plane parallel to the yz-plane at x = 1.
  • The plane y = 0 is the xz-plane.
  • The plane z = 0 is the xy-plane.
  • The parabolic cylinder y = x^2 opens along the y-axis.
  • The surface z = xey is a surface that increases as x and y increase.

Step 2: Set up the triple integral

The volume V of the solid is given by the triple integral of dV over the region D bounded by the given planes and surfaces. In this case, we integrate over y first (from 0 to x^2), then over x (from 0 to 1), and finally over z (from 0 to xey):

V = ∫ from 0 to 1 ∫ from 0 to x^2 ∫ from 0 to xey dz dy dx

Step 3: Evaluate the triple integral

First, we integrate with respect to z. The integral of dz from 0 to xey is simply xey - 0 = xey.

Then, we integrate with respect to y. The integral of xey dy from 0 to x^2 is [xey*y] from 0 to x^2 = x^3e^x^2 - 0 = x^3e^x^2.

Finally, we integrate with respect to x. The integral of x^3e^x^2 dx from 0 to 1 is a bit more complicated and requires the use of integration by substitution or a table of integrals. The result is e - 1.

So, the volume of the solid is V = e - 1 cubic units.

Please note that this is a simplified explanation and the actual calculations, especially the final integral, may require more advanced techniques of integration.

This problem has been solved

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