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A 3.00 m long air column is open at both ends. The frequency of a certain harmonic is 500 Hz and the frequency of the next higher harmonic is 557 Hz. Determine the speed of sound in the air column. The end correction may be neglected.

Question

A 3.00 m long air column is open at both ends. The frequency of a certain harmonic is 500 Hz and the frequency of the next higher harmonic is 557 Hz. Determine the speed of sound in the air column. The end correction may be neglected.

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Solution

Sure, let's solve this step by step:

Step 1: Identify the given values.

  • Length of the air column (L) = 3.00 m
  • Frequency of a certain harmonic (f1) = 500 Hz
  • Frequency of the next higher harmonic (f2) = 557 Hz

Step 2: Understand the concept.

  • For an air column open at both ends, the harmonics are given by the formula: f = n(v/2L), where n is the harmonic number (an integer), v is the speed of sound, and L is the length of the column.
  • The difference between two consecutive harmonics (n and n+1) is Δf = f2 - f1 = v/2L.

Step 3: Substitute the given values into the formula.

  • Δf = f2 - f1 = 557 Hz - 500 Hz = 57 Hz
  • So, 57 Hz = v/2L

Step 4: Solve for v, the speed of sound.

  • v = 2L * Δf = 2 * 3.00 m * 57 Hz = 342 m/s

So, the speed of sound in the air column is 342 m/s.

This problem has been solved

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