A resonance occurs with a tuning fork and air column of size 12cm. the next higher resonance occurs with an air column of 38cm. What is the frequency of the tuning fork? Assume that the speed of sound is 312m/s
Question
A resonance occurs with a tuning fork and air column of size 12cm. the next higher resonance occurs with an air column of 38cm. What is the frequency of the tuning fork? Assume that the speed of sound is 312m/s
Solution
To find the frequency of the tuning fork, we first need to understand that the difference in length between two resonances in an open tube is equal to one wavelength (λ).
Step 1: Calculate the Wavelength The difference in length between the two resonances is 38cm - 12cm = 26cm. Convert this to meters by dividing by 100, so λ = 0.26m.
Step 2: Calculate the Frequency The speed of sound (v) is given as 312m/s. The formula to find the frequency (f) is:
f = v / λ
Substitute the given values into the formula:
f = 312m/s / 0.26m = 1200 Hz
So, the frequency of the tuning fork is 1200 Hz.
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