The frequency of a tuning fork is 300 Hz. If the velocity of sound is 324 m/s; find the distance between a compression and the next rarefaction.Select an answerA5.14 cmB10.8 cmC54 cmD108 cm
Question
The frequency of a tuning fork is 300 Hz. If the velocity of sound is 324 m/s; find the distance between a compression and the next rarefaction.Select an answerA5.14 cmB10.8 cmC54 cmD108 cm
Solution
To solve this problem, we need to understand a few basic concepts about sound waves.
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Sound waves are longitudinal waves, which means they consist of compressions and rarefactions. The distance between a compression and the next rarefaction is half of a wavelength.
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The speed of sound (v) is equal to the frequency (f) times the wavelength (λ). This can be written as: v = f * λ
Now, let's use these concepts to solve the problem:
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We know the frequency (f) is 300 Hz and the speed of sound (v) is 324 m/s. We can use these values to find the wavelength (λ) using the formula: v = f * λ
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Rearranging the formula to solve for λ gives us: λ = v / f
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Substituting the given values into the formula gives us: λ = 324 m/s / 300 Hz = 1.08 m
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Remember, the distance between a compression and the next rarefaction is half of a wavelength. So, we divide the wavelength by 2 to get this distance: 1.08 m / 2 = 0.54 m
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Convert this distance from meters to centimeters (since the answer choices are given in centimeters): 0.54 m * 100 = 54 cm
So, the distance between a compression and the next rarefaction is 54 cm. Therefore, the correct answer is C) 54 cm.
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