What will be the output of the following program set = {"apple", "banana", "orange"} x = set.pop() print(x) print(set) Options apple {"banana", "orange"} banana {"apple", "orange"} Both i and ii None of the Above
Question
What will be the output of the following program
set = {"apple", "banana", "orange"}
x = set.pop()
print(x)
print(set)
Options apple {"banana", "orange"} banana {"apple", "orange"} Both i and ii None of the Above
Solution
The correct answer is "Both i and ii".
The pop() method in Python removes an arbitrary element from the set and returns it. This method modifies the set. Since sets are unordered collections of unique elements, there's no "last element" or "first element". When you pop an element from the set, a random element is removed.
Therefore, the output could be either "apple {"banana", "orange"}" or "banana {"apple", "orange"}", depending on which element is randomly popped from the set.
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