What will be the output of the following Python code snippet?v=set('code')v.add('tantra')v.update(set(['p', 'q']))print(v)Options{‘c’, ‘o’, ‘d’, ‘e’, ‘p’,'q', ‘tantra’}{‘c’, ‘o’, ‘d’, ‘e’, [‘p’, 'q'], ‘tantra’}{'code', ‘p’, 'q', ‘tantra’}{'d', 't', 'a', 'n', 't', 'r,' 'a', 'p', 'q', 'o', 'e', 'c'}
Question
What will be the output of the following Python code snippet?v=set('code')v.add('tantra')v.update(set(['p', 'q']))print(v)Options{‘c’, ‘o’, ‘d’, ‘e’, ‘p’,'q', ‘tantra’}{‘c’, ‘o’, ‘d’, ‘e’, [‘p’, 'q'], ‘tantra’}{'code', ‘p’, 'q', ‘tantra’}{'d', 't', 'a', 'n', 't', 'r,' 'a', 'p', 'q', 'o', 'e', 'c'}
Solution
The output of the given Python code snippet will be:
{‘c’, ‘o’, ‘d’, ‘e’, ‘p’,'q', ‘tantra’}
Here's the step by step explanation:
-
v=set('code')- This will create a set with the individual characters of the string 'code', i.e., {'c', 'o', 'd', 'e'}. -
v.add('tantra')- This will add the string 'tantra' as a single element to the set, making the set {'c', 'o', 'd', 'e', 'tantra'}. -
v.update(set(['p', 'q']))- The update() method updates the set, adding elements from another set. Here, it adds 'p' and 'q' to the set, resulting in the set {'c', 'o', 'd', 'e', 'p', 'q', 'tantra'}. -
print(v)- This will print the final set, which is {‘c’, ‘o’, ‘d’, ‘e’, ‘p’,'q', ‘tantra’}.
Similar Questions
Select the correct answerWhat will be the output of the following Python code snippet?d_1 = {"code":10, "tantra":15}print(list(d_1.keys()))Options(“code”:10, “tantra”:15)['code', 'tantra'][“code”:10, “tantra”:15](“code”, “tantra”)
What is the output of the following?ct = ['code', 'tantra']for x in ct: ct.append(x.upper())print(ct)OptionsNone of these[‘code’, ‘tantra’].[‘CODE’, ‘TANTRA’].[None, None].
What is the output of the following program?c = ['code', 'tantra']for t in c: t.upper()print(c)Options['code', 'tantra']CODE['CODE' , 'TANTRA']TANTRA
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What will be the output of the following Python code?a=set()type(a)Options<’set’>setclass set<class ‘set’>
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