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What will be the output of the following Python code snippet?a={1:"A",2:"B",3:"C"}a.setdefault(4,"D")print(a){1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}NoneError[1,3,6,10]

Question

What will be the output of the following Python code snippet?a={1:"A",2:"B",3:"C"}a.setdefault(4,"D")print(a){1: ‘A’, 2: ‘B’, 3: ‘C’, 4: ‘D’}NoneError[1,3,6,10]

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Solution

The output of the given Python code snippet will be:

{1: 'A', 2: 'B', 3: 'C', 4: 'D'}

Here's the step by step explanation:

  1. We have a dictionary 'a' with keys 1, 2, 3 and corresponding values 'A', 'B', 'C'.

  2. The setdefault() method in Python is a built-in method used for dictionary handling. It returns the value of a key (if the key is in dictionary). If not, it inserts key with a value to the dictionary.

  3. In the code, a.setdefault(4,"D") is used. Here, 4 is not a key in the dictionary. So, it will add 4:"D" to the dictionary 'a'.

  4. Finally, when we print the dictionary 'a', it will output {1: 'A', 2: 'B', 3: 'C', 4: 'D'} as 4:"D" has been added to the original dictionary.

This problem has been solved

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1/3

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