A Single phase PFC Circuit is required to be designed for the following Specs:Rated output power Po: 2.5kW AC input voltage range: 100-270VAC Grid frequency range: 50±1HzOutput DC voltage 400VSwitch frequency fsw: 120kHz Efficiency h: >94% Therefore: The Peak Value of the boost inductor current is Select one:a. 25 Ab. 13 Ac. None of the given choicesd. 35.35 A
Question
A Single phase PFC Circuit is required to be designed for the following Specs:Rated output power Po: 2.5kW AC input voltage range: 100-270VAC Grid frequency range: 50±1HzOutput DC voltage 400VSwitch frequency fsw: 120kHz Efficiency h: >94% Therefore: The Peak Value of the boost inductor current is Select one:a. 25 Ab. 13 Ac. None of the given choicesd. 35.35 A
Solution
To solve this problem, we need to use the formula for the peak value of the boost inductor current in a Power Factor Correction (PFC) circuit. The formula is:
Ip = Po / (2 * Vin_min * h)
where:
- Ip is the peak value of the boost inductor current,
- Po is the rated output power,
- Vin_min is the minimum AC input voltage, and
- h is the efficiency.
Given:
- Po = 2.5 kW = 2500 W,
- Vin_min = 100 V, and
- h = 94% = 0.94,
we can substitute these values into the formula:
Ip = 2500 W / (2 * 100 V * 0.94) = 13.3 A
So, the closest answer is:
b. 13 A
Similar Questions
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