A Single phase PFC Circuit is required to be designed for the following Specs:Rated output power Po: 2.5kW AC input voltage range: 100-270VAC Grid frequency range: 50±1Hz d.Output DC voltage 400VSwitch frequency fsw: 120kHz Efficiency h: >94% Therefore: The Max Duty Cycle Value is Select one:a. 0.45b. 0.65c. 0.8d. 0.9
Question
A Single phase PFC Circuit is required to be designed for the following Specs:Rated output power Po: 2.5kW AC input voltage range: 100-270VAC Grid frequency range: 50±1Hz d.Output DC voltage 400VSwitch frequency fsw: 120kHz Efficiency h: >94% Therefore: The Max Duty Cycle Value is Select one:a. 0.45b. 0.65c. 0.8d. 0.9
Solution
The maximum duty cycle (Dmax) for a single phase PFC circuit can be calculated using the following formula:
Dmax = 1 - (Vin(min) / Vout)
Where: Vin(min) is the minimum input AC voltage Vout is the output DC voltage
Given in the problem: Vin(min) = 100V Vout = 400V
Substituting these values into the formula gives:
Dmax = 1 - (100 / 400) = 1 - 0.25 = 0.75
However, this is not one of the options given in the problem. It's possible there may be a mistake in the problem or in the given options. Based on the calculated value, the closest option would be 0.8 (option c), but this is not an exact match.
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