he product of two numbers is 4107. If the HCF of these numbers is 37, then the greater number is:Choices:- 101 107 111 185
Question
he product of two numbers is 4107. If the HCF of these numbers is 37, then the greater number is:Choices:- 101 107 111 185
Solution
The problem states that the product of two numbers is 4107 and their highest common factor (HCF) is 37.
We know that the product of two numbers is equal to the product of their HCF and their least common multiple (LCM).
So, if we let the two numbers be 37a and 37b (where a and b are co-prime numbers, meaning their HCF is 1), then:
37a * 37b = 4107 a * b = 4107 / (37*37) a * b = 3
The pairs of co-prime numbers that multiply to 3 are (1,3) and (3,1).
So, the two numbers are 371 = 37 and 373 = 111.
Therefore, the greater number is 111.
So, the correct choice is 111.
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