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The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

Question

The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

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Solution

Step 1: We know that the product of two numbers is equal to the product of their H.C.F. and L.C.M.

So, let's denote the two numbers as a and b, their H.C.F. as h and their L.C.M. as l. We have:

a * b = h * l

Step 2: We are given that a * b = 4107 and h = 37. We can substitute these values into the equation:

4107 = 37 * l

Step 3: Solve for l:

l = 4107 / 37 = 111

Step 4: Now we know that the numbers a and b are factors of 4107 that also have a H.C.F. of 37. Since 37 is a factor of 4107, the other factors will be 37 and 111.

Step 5: Therefore, the greater number is 111.

This problem has been solved

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