A,B and C play a game and the chances of their winning it in an attempt are (2/3), (1/2) and (1/4) respectively. A has the first chance, followed by B and then by C. This cycle is repeated till one of them wins the game. Then the probability that B wins is*4/2116/218/211/21
Question
A,B and C play a game and the chances of their winning it in an attempt are (2/3), (1/2) and (1/4) respectively. A has the first chance, followed by B and then by C. This cycle is repeated till one of them wins the game. Then the probability that B wins is*4/2116/218/211/21
Solution
The problem is asking for the probability that player B wins the game.
The game is played in cycles, with player A going first, then player B, and finally player C. This cycle continues until one player wins.
The probability that a player wins on their turn is independent of previous turns, so we can calculate the probability of each player winning on their turn and then use these probabilities to calculate the overall probability of player B winning.
The probability that player A wins on their turn is 2/3, the probability that player B wins on their turn is 1/2, and the probability that player C wins on their turn is 1/4.
However, for player B to win, player A must first lose on their turn, and then player B must win on their turn. The probability of this happening is (1 - 2/3) * (1/2) = 1/3 * 1/2 = 1/6.
Similarly, for player B to win in the second cycle, players A and C must both lose on their turns, and then player B must win on their turn. The probability of this happening is (1 - 2/3) * (1 - 1/4) * (1/2) = 1/3 * 3/4 * 1/2 = 1/8.
We can continue this process for each subsequent cycle, but the probabilities will get smaller and smaller.
Therefore, the overall probability of player B winning is the sum of the probabilities of player B winning in each cycle. This sum is a geometric series with first term 1/6 and common ratio 1/8.
The sum of an infinite geometric series with first term a and common ratio r is given by the formula a / (1 - r).
Therefore, the probability that player B wins is 1/6 / (1 - 1/8) = 1/6 / 7/8 = 8/42 = 4/21.
So, the correct answer is 4/21.
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