f f(x,y) = 4x2 + 3y2, then f(1, 2) = 17 15 11 16 None of these
Question
f f(x,y) = 4x2 + 3y2, then f(1, 2) =
17
15
11
16
None of these
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Solution
To solve this problem, we need to substitute the values of x and y into the function f(x,y).
The function is f(x,y) = 4x^2 + 3y^2.
Substitute x = 1 and y = 2 into the function:
f(1,2) = 4*(1)^2 + 3*(2)^2 = 41 + 34 = 4 + 12 = 16
So, the answer is 16.
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