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f f(x,y) = 4x2 + 3y2, then f(1, 2) = 17 15 11 16 None of these

Question

f f(x,y) = 4x2 + 3y2, then f(1, 2) =

17

15

11

16

None of these

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Solution

To solve this problem, we need to substitute the values of x and y into the function f(x,y).

The function is f(x,y) = 4x^2 + 3y^2.

Substitute x = 1 and y = 2 into the function:

f(1,2) = 4*(1)^2 + 3*(2)^2 = 41 + 34 = 4 + 12 = 16

So, the answer is 16.

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