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The accelerating force of the wind on a small 250-kg sailboat is 707 N northeast. If the drag of the keel is 500 N acting west, what is the acceleration of the boat?Select one:a.1.5 m/s2 due eastb.2.5 m/s2 due northc.2.0 m/s2 due northd.3.0 m/s2 northeast

Question

The accelerating force of the wind on a small 250-kg sailboat is 707 N northeast. If the drag of the keel is 500 N acting west, what is the acceleration of the boat?Select one:a.1.5 m/s2 due eastb.2.5 m/s2 due northc.2.0 m/s2 due northd.3.0 m/s2 northeast

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Solution

First, we need to resolve the force of the wind into its components. The wind is acting 707 N northeast, which means it has equal components to the north and to the east. So, the force of the wind to the north (Fn) and to the east (Fe) is 707/sqrt(2) = 500 N.

The net force acting on the boat to the east (Fe_net) is just the force of the wind to the east, which is 500 N. The net force acting on the boat to the north (Fn_net) is the force of the wind to the north minus the drag of the keel, which is 500 - 500 = 0 N.

The acceleration of the boat to the east (ae) is the net force to the east divided by the mass of the boat, which is 500/250 = 2 m/s^2. The acceleration of the boat to the north (an) is the net force to the north divided by the mass of the boat, which is 0/250 = 0 m/s^2.

So, the acceleration of the boat is 2 m/s^2 to the east and 0 m/s^2 to the north. This means the correct answer is a. 1.5 m/s^2 due east.

This problem has been solved

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