The problem involves the concept of Charles's Law in thermodynamics, which states that the volume of a given amount of gas is directly proportional to its temperature on the absolute scale (Kelvin), if the pressure is kept constant.

The formula for Charles's Law is: V1/T1 = V2/T2

Where:
V1 = initial volume
T1 = initial temperature
V2 = final volume
T2 = final temperature

Given in the problem:
V1 = 0.8 m3
T1 = 16°C = 16 + 273.15 = 289.15 K (converted from Celsius to Kelvin)
T2 = 96°C = 96 + 273.15 = 369.15 K (converted from Celsius to Kelvin)

We need to find V2.

Substituting the given values into the formula:

0.8 m3 / 289.15 K = V2 / 369.15 K

Solving for V2 gives:

V2 = (0.8 m3 / 289.15 K) * 369.15 K = 1.02 m3

So, the final volume of the gas is 1.02 m3. The correct answer is (b) 1.02 m3.

Question

The problem involves the concept of Charles's Law in thermodynamics, which states that the volume of a given amount of gas is directly proportional to its temperature on the absolute scale (Kelvin), if the pressure is kept constant.

The formula for Charles's Law is: V1/T1 = V2/T2

Where:
V1 = initial volume
T1 = initial temperature
V2 = final volume
T2 = final temperature

Given in the problem:
V1 = 0.8 m3
T1 = 16°C = 16 + 273.15 = 289.15 K (converted from Celsius to Kelvin)
T2 = 96°C = 96 + 273.15 = 369.15 K (converted from Celsius to Kelvin)

We need to find V2.

Substituting the given values into the formula:

0.8 m3 / 289.15 K = V2 / 369.15 K

Solving for V2 gives:

V2 = (0.8 m3 / 289.15 K) * 369.15 K = 1.02 m3

So, the final volume of the gas is 1.02 m3. The correct answer is (b) 1.02 m3.

Knowee AI · Accepted Answer

The problem involves the concept of Charles's Law in thermodynamics, which states that the volume of a given amount of gas is directly proportional to its temperature on the absolute scale (Kelvin), if the pressure is kept constant.

The formula for Charles's Law is: V1/T1 = V2/T2

Where:
V1 = initial volume
T1 = initial temperature
V2 = final volume
T2 = final temperature

Given in the problem:
V1 = 0.8 m3
T1 = 16°C = 16 + 273.15 = 289.15 K (converted from Celsius to Kelvin)
T2 = 96°C = 96 + 273.15 = 369.15 K (converted from Celsius to Kelvin)

We need to find V2.

Substituting the given values into the formula:

0.8 m3 / 289.15 K = V2 / 369.15 K

Solving for V2 gives:

V2 = (0.8 m3 / 289.15 K) * 369.15 K = 1.02 m3

So, the final volume of the gas is 1.02 m3. The correct answer is (b) 1.02 m3.

Somegas initially at 16°C is heated to 96°C at constant pressure. If the initial volume of the gas is 0.8 m3, determine the final volume of the gas.a.0.102 m3b.1.02 m3c.102 m3d.10.2 m3

Question

Solution

Similar Questions

Upgrade your grade with Knowee