To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas remain constant. The formula for Charles's Law is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Step 1: Convert the initial temperature from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 100°C + 273.15 = 373.15 K.

Step 2: Substitute the known values into Charles's Law and solve for T2.

V1/T1 = V2/T2
3.0 m3 / 373.15 K = 6.0 m3 / T2

Step 3: Solve for T2.

T2 = (6.0 m3 * 373.15 K) / 3.0 m3 = 746.3 K

So, the final temperature of the gas is 746.3 K.

Question

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas remain constant. The formula for Charles's Law is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Step 1: Convert the initial temperature from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 100°C + 273.15 = 373.15 K.

Step 2: Substitute the known values into Charles's Law and solve for T2.

V1/T1 = V2/T2
3.0 m3 / 373.15 K = 6.0 m3 / T2

Step 3: Solve for T2.

T2 = (6.0 m3 * 373.15 K) / 3.0 m3 = 746.3 K

So, the final temperature of the gas is 746.3 K.

Knowee AI · Accepted Answer

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas remain constant. The formula for Charles's Law is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.

Step 1: Convert the initial temperature from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 100°C + 273.15 = 373.15 K.

Step 2: Substitute the known values into Charles's Law and solve for T2.

V1/T1 = V2/T2
3.0 m3 / 373.15 K = 6.0 m3 / T2

Step 3: Solve for T2.

T2 = (6.0 m3 * 373.15 K) / 3.0 m3 = 746.3 K

So, the final temperature of the gas is 746.3 K.

A sample of oxygen gas with a volume of 3.0 m 3 is at 100 °C. The gas is heated so that itexpands at a constant pressure to a final volume of 6.0 m3. What is the final temperatureof the gas?

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