To solve this problem, we need to use the equations of motion.

First, we need to find the initial velocity components. The initial velocity in the x-direction (Vx) and y-direction (Vy) can be found using the initial speed and the angle:

Vx = 18.7 m/s * cos(38.5) = 14.6 m/s
Vy = 18.7 m/s * sin(38.5) = 11.5 m/s

Next, we need to find the time the football is in the air. We can use the equation of motion in the y-direction:

Vy*t - 0.5*g*t^2 = 0

Solving for t gives us two times, at the start when the ball is kicked and at the end when the ball lands. We are interested in the latter:

t = 2*Vy / g = 2*11.5 m/s / 9.8 m/s^2 = 2.35 s

Finally, we can find the horizontal distance the football travels using the equation of motion in the x-direction:

d = Vx*t = 14.6 m/s * 2.35 s = 34.3 m

So, the football lands approximately 34.3 m from the original kick. The closest answer is 34.8 m.

Question

To solve this problem, we need to use the equations of motion.

First, we need to find the initial velocity components. The initial velocity in the x-direction (Vx) and y-direction (Vy) can be found using the initial speed and the angle:

Vx = 18.7 m/s * cos(38.5) = 14.6 m/s
Vy = 18.7 m/s * sin(38.5) = 11.5 m/s

Next, we need to find the time the football is in the air. We can use the equation of motion in the y-direction:

Vy*t - 0.5*g*t^2 = 0

Solving for t gives us two times, at the start when the ball is kicked and at the end when the ball lands. We are interested in the latter:

t = 2*Vy / g = 2*11.5 m/s / 9.8 m/s^2 = 2.35 s

Finally, we can find the horizontal distance the football travels using the equation of motion in the x-direction:

d = Vx*t = 14.6 m/s * 2.35 s = 34.3 m

So, the football lands approximately 34.3 m from the original kick. The closest answer is 34.8 m.

Knowee AI · Accepted Answer

To solve this problem, we need to use the equations of motion.

First, we need to find the initial velocity components. The initial velocity in the x-direction (Vx) and y-direction (Vy) can be found using the initial speed and the angle:

Vx = 18.7 m/s * cos(38.5) = 14.6 m/s
Vy = 18.7 m/s * sin(38.5) = 11.5 m/s

Next, we need to find the time the football is in the air. We can use the equation of motion in the y-direction:

Vy*t - 0.5*g*t^2 = 0

Solving for t gives us two times, at the start when the ball is kicked and at the end when the ball lands. We are interested in the latter:

t = 2*Vy / g = 2*11.5 m/s / 9.8 m/s^2 = 2.35 s

Finally, we can find the horizontal distance the football travels using the equation of motion in the x-direction:

d = Vx*t = 14.6 m/s * 2.35 s = 34.3 m

So, the football lands approximately 34.3 m from the original kick. The closest answer is 34.8 m.

A football is kicked up in the air with an initial speed of 18.7 m/s and at an angle of 38.5o above the horizontal. How far from the original kick does it land? 55.9 m 34.8 m 17.4 m 44.4 m

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