To find the current flowing through the 12 Ω resistor, we first need to find the total resistance in the circuit. Since the resistors are connected in series, we simply add up all the resistances:

R_total = 0.2 Ω + 0.3 Ω + 0.4 Ω + 0.5 Ω + 12 Ω = 13.4 Ω

Next, we use Ohm's law, which states that the current I is equal to the voltage V divided by the resistance R. In this case, the voltage is provided by the 9 V battery:

I = V / R_total = 9 V / 13.4 Ω = 0.67 A

Therefore, the current flowing through the 12 Ω resistor is 0.67 A.

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To find the current flowing through the 12 Ω resistor, we first need to find the total resistance in the circuit. Since the resistors are connected in series, we simply add up all the resistances:

R_total = 0.2 Ω + 0.3 Ω + 0.4 Ω + 0.5 Ω + 12 Ω = 13.4 Ω

Next, we use Ohm's law, which states that the current I is equal to the voltage V divided by the resistance R. In this case, the voltage is provided by the 9 V battery:

I = V / R_total = 9 V / 13.4 Ω = 0.67 A

Therefore, the current flowing through the 12 Ω resistor is 0.67 A.

Knowee AI · Accepted Answer

To find the current flowing through the 12 Ω resistor, we first need to find the total resistance in the circuit. Since the resistors are connected in series, we simply add up all the resistances:

R_total = 0.2 Ω + 0.3 Ω + 0.4 Ω + 0.5 Ω + 12 Ω = 13.4 Ω

Next, we use Ohm's law, which states that the current I is equal to the voltage V divided by the resistance R. In this case, the voltage is provided by the 9 V battery:

I = V / R_total = 9 V / 13.4 Ω = 0.67 A

Therefore, the current flowing through the 12 Ω resistor is 0.67 A.

A battery of 9 V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.4 Ω , 0.5 Ωand 12 Ω, respectively. How much current would flow through the 12 Ω resistor?

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