Calculate the current flowing through the 10Ω resistor in the following circuit.(a) 0.6 A(b) 1.2 A(c) 2.0 A(d) 0.2 A
Question
Calculate the current flowing through the 10Ω resistor in the following circuit.(a) 0.6 A(b) 1.2 A(c) 2.0 A(d) 0.2 A
Solution
To calculate the current flowing through the 10Ω resistor in the given circuit, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.
In this case, we need to find the voltage across the 10Ω resistor. To do this, we can use Kirchhoff's Voltage Law (KVL), which states that the sum of the voltages in a closed loop in a circuit is equal to zero.
Looking at the circuit, we can see that there is a 6V battery connected in series with a 4Ω resistor and a 10Ω resistor. Let's assume that the current flowing through the circuit is I.
Using KVL, we can write the equation: 6V - 4Ω * I - 10Ω * I = 0
Simplifying the equation, we get: 6V - 14Ω * I = 0
Now, we can solve for I: 14Ω * I = 6V I = 6V / 14Ω I ≈ 0.4286 A
Therefore, the current flowing through the 10Ω resistor is approximately 0.4286 A.
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