Which function defines (๐รท๐)โข(๐ฅ) ?๐โก(๐ฅ)=(3.6)๐ฅ+2๐โก(๐ฅ)=(3.6)3โข๐ฅ+1 A. (๐รท๐)โข(๐ฅ)=(3.6)-2โข๐ฅ+1 B. (๐รท๐)โข(๐ฅ)=(3.6)4โข๐ฅ+3 C. (๐รท๐)โข(๐ฅ)=(1.8)3โข๐ฅ2+7โข๐ฅ+2 D.
Question
Which function defines (๐รท๐)โข(๐ฅ) ?๐โก(๐ฅ)=(3.6)๐ฅ+2๐โก(๐ฅ)=(3.6)3โข๐ฅ+1 A. (๐รท๐)โข(๐ฅ)=(3.6)-2โข๐ฅ+1 B. (๐รท๐)โข(๐ฅ)=(3.6)4โข๐ฅ+3 C. (๐รท๐)โข(๐ฅ)=(1.8)3โข๐ฅ2+7โข๐ฅ+2 D.
Solution
The function (๐รท๐)(๐ฅ) is defined as the ratio of the function ๐(๐ฅ) to the function ๐(๐ฅ).
Given ๐(๐ฅ) = (3.6)๐ฅ + 2 and ๐(๐ฅ) = (3.6)3๐ฅ + 1, we can find (๐รท๐)(๐ฅ) by dividing ๐(๐ฅ) by ๐(๐ฅ):
(๐รท๐)(๐ฅ) = [(3.6)๐ฅ + 2] / [(3.6)3๐ฅ + 1]
This is a complex rational function and cannot be simplified to a form like the options A, B, C, and D. Therefore, none of the given options correctly defines (๐รท๐)(๐ฅ).
Similar Questions
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