The integral of -3x with respect to x is -3/2 * x^2 + C, where C is the constant of integration.

Here are the steps:

1. Identify the function to be integrated, which is -3x in this case.
2. Apply the power rule for integration, which states ∫x^n dx = (1/n+1)x^(n+1) + C, where n ≠ -1. Here, n is 1.
3. Substituting the values, we get ∫-3x dx = -3 * (1/(1+1))x^(1+1) + C = -3/2 * x^2 + C.

Question

The integral of -3x with respect to x is -3/2 * x^2 + C, where C is the constant of integration.

Here are the steps:

1. Identify the function to be integrated, which is -3x in this case.
2. Apply the power rule for integration, which states ∫x^n dx = (1/n+1)x^(n+1) + C, where n ≠ -1. Here, n is 1.
3. Substituting the values, we get ∫-3x dx = -3 * (1/(1+1))x^(1+1) + C = -3/2 * x^2 + C.

Knowee AI · Accepted Answer

The integral of -3x with respect to x is -3/2 * x^2 + C, where C is the constant of integration.

Here are the steps:

1. Identify the function to be integrated, which is -3x in this case.
2. Apply the power rule for integration, which states ∫x^n dx = (1/n+1)x^(n+1) + C, where n ≠ -1. Here, n is 1.
3. Substituting the values, we get ∫-3x dx = -3 * (1/(1+1))x^(1+1) + C = -3/2 * x^2 + C.

valuate the following.∫(−3𝑥)d𝑥=

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