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If ๐’‚:๐’ƒ:๐’„=๐Ÿ:๐Ÿ‘:๐Ÿ“, what is the value of ๐Ÿ’๐’‚โˆ’๐’ƒ+๐Ÿ๐’„/3(๐’‚+๐’ƒ+๐’„)?Options8/2711/271/310/27

Question

If ๐’‚:๐’ƒ:๐’„=๐Ÿ:๐Ÿ‘:๐Ÿ“, what is the value of ๐Ÿ’๐’‚โˆ’๐’ƒ+๐Ÿ๐’„/3(๐’‚+๐’ƒ+๐’„)?Options8/2711/271/310/27

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Solution

The given ratio is a:b:c = 1:3:5.

Step 1: Let's find the value of 4a - b + 2c. Substitute the given ratio values into the equation.

4a - b + 2c = 4(1) - 3 + 2(5) = 4 - 3 + 10 = 11.

Step 2: Now, let's find the value of 3(a + b + c). Substitute the given ratio values into the equation.

3(a + b + c) = 3(1 + 3 + 5) = 3(9) = 27.

Step 3: Now, let's find the value of (4a - b + 2c) / 3(a + b + c). Substitute the values from steps 1 and 2 into the equation.

(4a - b + 2c) / 3(a + b + c) = 11 / 27.

So, the value of (4a - b + 2c) / 3(a + b + c) is 11/27.

This problem has been solved

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