In which of the following cases will work NOT be done on an object by the action of a force?When the object is moving very slowlyWhen the magnitude (size) of the force changes with timeWhen the force which is acting is small compared to the weight of the objectWhen the object does not move in the direction of the force2Which of the following will cause one joule (1 J) of work to be done on (energy to be transferred to) an object?A force of 1 N causing the object to move through a distance of 1 cmA force of 10 N causing the object to move through a distance of 10 cmA force of 100 N causing the object to move through 10 mA force of 5 N causing the object to move through 0.1 m3
Question
In which of the following cases will work NOT be done on an object by the action of a force?When the object is moving very slowlyWhen the magnitude (size) of the force changes with timeWhen the force which is acting is small compared to the weight of the objectWhen the object does not move in the direction of the force2Which of the following will cause one joule (1 J) of work to be done on (energy to be transferred to) an object?A force of 1 N causing the object to move through a distance of 1 cmA force of 10 N causing the object to move through a distance of 10 cmA force of 100 N causing the object to move through 10 mA force of 5 N causing the object to move through 0.1 m3
Solution
The text you provided seems to be incomplete and a bit confusing. However, I'll try to answer based on what I understood.
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Work will NOT be done on an object by the action of a force in the case when the object does not move in the direction of the force. Work is defined as the product of the force and the displacement of the object in the direction of the force. If there is no displacement in the direction of the force, then no work is done.
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One joule (1 J) of work will be done on an object when a force of 1 N causes the object to move through a distance of 1 m. The formula for work is Work = Force x Distance. So, if the force is 1 N and the distance is 1 m, then the work done is 1 J. The options you provided do not match this condition. The closest is the last option where a force of 5 N causes the object to move through 0.1 m, which results in 0.5 J of work, not 1 J.
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